<?xml version="1.0" encoding="utf-8" standalone="yes"?><rss version="2.0" xmlns:atom="http://www.w3.org/2005/Atom"><channel><title>Jaynes-Cummings on Haifei's Home</title><link>https://haifei.pro/en/tags/jaynes-cummings/</link><description>Recent content in Jaynes-Cummings on Haifei's Home</description><generator>Hugo</generator><language>en</language><managingEditor>hfwang132@gmail.com (hfwang132)</managingEditor><webMaster>hfwang132@gmail.com (hfwang132)</webMaster><copyright>This work is licensed under a Creative Commons Attribution-NonCommercial 4.0 International License.</copyright><lastBuildDate>Sun, 13 Apr 2025 01:52:37 +0800</lastBuildDate><atom:link href="https://haifei.pro/en/tags/jaynes-cummings/index.xml" rel="self" type="application/rss+xml"/><item><title>From Quantum Field Theory to Cavity Quantum Electrodynamics [Higher and More Subtle Electrodynamics · 6]</title><link>https://haifei.pro/en/post_20250413_%E4%BB%8E%E9%87%8F%E5%AD%90%E5%9C%BA%E8%AE%BA%E5%88%B0%E8%85%94%E9%87%8F%E5%AD%90%E7%94%B5%E5%8A%A8%E5%8A%9B%E5%AD%A6-%E6%9B%B4%E9%AB%98%E6%9B%B4%E5%A6%99%E7%9A%84%E7%94%B5%E5%8A%A8%E5%8A%9B%E5%AD%A6-5/</link><pubDate>Sun, 13 Apr 2025 01:52:37 +0800</pubDate><author>hfwang132@gmail.com (hfwang132)</author><guid>https://haifei.pro/en/post_20250413_%E4%BB%8E%E9%87%8F%E5%AD%90%E5%9C%BA%E8%AE%BA%E5%88%B0%E8%85%94%E9%87%8F%E5%AD%90%E7%94%B5%E5%8A%A8%E5%8A%9B%E5%AD%A6-%E6%9B%B4%E9%AB%98%E6%9B%B4%E5%A6%99%E7%9A%84%E7%94%B5%E5%8A%A8%E5%8A%9B%E5%AD%A6-5/</guid><description>&lt;p&gt;In this article, we start from the QED Lagrangian:&lt;/p&gt;
\[\begin{aligned} \mathcal{L}= \bar{\psi}(\mathrm{i}\gamma^\mu \partial_\mu -m)\psi - eA_\mu \bar{\psi} \gamma^\mu \psi -\frac{1}{4} F_{\mu\nu} F^{\mu\nu} \end{aligned} \]&lt;p&gt;This Lagrangian is highly complex: it not only takes into account the electron&amp;rsquo;s antiparticle—the positron—but the coupling term \(- eA_\mu \bar{\psi} \gamma^\mu \psi\) is also a cubic term, capable of describing various processes such as electron-positron pair creation/annihilation. Due to the presence of the cubic term, this Lagrangian has no analytic solution and can only be solved using perturbation theory in quantum field theory.&lt;/p&gt;</description></item></channel></rss>